Last updated 2 months ago
class Solution: def firstBadVersion(self, n: int) -> int: return self.bs(1, n) def bs(self, l, r): while r > l: mid = l + (r - l) // 2 if isBadVersion(mid): r = mid else: l = mid + 1 return l
时间复杂度:O(log(n)) 空间复杂度:O(1)