class Solution:
def removeDuplicates(self, s: str, k: int) -> str:
stack = []
for char in s:
if stack and stack[-1][0] == char:
stack[-1][1] += 1
if stack [-1][1] == k:
stack.pop()
# 注意这里有else
else:
# 注意上面有修改 stack[-1][1]的值,因此只能选list,不能tuple
stack.append([char, 1])
return "".join(c*count for c, count in stack)